Start free

Mathematics · Permutations and Combinations

JEE Main 2025 — 28 January, Morning Shift — Question 1

The number of different 5 digit numbers greater than 50000 that can be formed using the digits 0,1 , 2,3,4,5,6,72,3,4,5,6,7, such that the sum of their first and last digits should not be more than 8 , is

  1. Option A:

    4608

  2. Option B:

    5720

  3. Option C:

    5719

  4. Option D:

    4607

    Correct

Answer: D

Step-by-step solution

figure

9×(8×8×8)=46089 \times(8 \times 8 \times 8)=4608 but 50000 is not included, so total numbers 4608−1=46074608-1=4607

Answer key and solution verified before publishing.

Practise Permutations and Combinations

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free
Exam
JEE Main 2025
Paper
28 January, Morning Shift
Subject
Mathematics
Chapter
Permutations and Combinations
Topic
Applications of Permuations and Combination
The number of different 5 digit numbers greater than 50000 that can… | JEE Main 2025 PYQ with Solution · DhiX AI