Mathematics · Permutations and Combinations

JEE Main 2026 — 6 April, Morning Shift — Question 27

The number of 4-letter words, with or without meaning, each consisting of two vowels and two consonants that can be formed from the letters of the word INCONSEQUENTIAL, without repeating any letter, is:

  1. Option A:

    2670

  2. Option B:

    2840

  3. Option C:

    2920

  4. Option D:

    3600

    Correct

Answer: D

Step-by-step solution

INCONSEQUENTIAL contains (I, E,O, A,U) and (N,C,S,Q,T,L)

Total number of 4 letter words using two vowels and two consonants is =5C2×6C2×4!={ }^{5} \mathrm{C}_{2} \times{ }^{6} \mathrm{C}_{2} \times 4! =3600=3600

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Mathematics
Chapter
Permutations and Combinations
Topic
Problems based on both permutations and combinations
The number of 4-letter words, with or without meaning, each… | JEE Main 2026 PYQ with Solution · DhiX AI