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Chemistry · Carboxylic Acids and Derivatives

JEE Main 2024 — 27 January, Shift 2 — Question 64

The molecular formula of second homologue in the homologous series of mono carboxylic acids is \qquad

  1. Option A:

    C3H6O2\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}_{2}

  2. Option B:

    C2H4O2\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{O}_{2}

    Correct
  3. Option C:

    CH2O\mathrm{CH}_{2} \mathrm{O}

  4. Option D:

    C2H2O2\mathrm{C}_{2} \mathrm{H}_{2} \mathrm{O}_{2}

Answer: B

Step-by-step solution

HCOOH,CH3COOH\mathrm{HCOOH}, \mathrm{CH}_{3} \mathrm{COOH}

                                   $\uparrow$

                         Second homologue

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
27 January, Shift 2
Subject
Chemistry
Chapter
Carboxylic Acids and Derivatives
Topic
Introduction and Preparation of Carboxylic Acids
The molecular formula of second homologue in the homologous series of… | JEE Main 2024 PYQ with Solution · DhiX AI