Chemistry · Electrochemistry

JEE Main 2024 — 27 January, Shift 1 — Question 73

The mass of silver (Molar mass of $\mathrm{Ag}: 108 \mathrm{gmol}^{-1}$ ) displaced by a quantity of electricity which displaces 5600 mL of $\mathrm{O}_{2}$ at S.T.P. will be $\qquad$ g.

Answer: 108

Numerical answer — enter this value.

Step-by-step solution

Eq. of $\mathrm{Ag}=$ Eq. of $\mathrm{O}_{2}$

Let x gm silver displaced,

$\frac{\mathrm{x} \times 1}{108}=\frac{5.6}{22.7} \times 4$

(Molar volume of gas at STP = 22.7 lit)

$x=106.57 \mathrm{gm}$

Ans. 107

OR,

as per old STP data, molar volume $=22.4$ lit

$\frac{\mathrm{x} \times 1}{108}=\frac{5.6}{22.4} \times 4, x=108 \mathrm{gm}$ .

Ans. 108

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 27 January, Shift 1
Subject: Chemistry
Chapter: Electrochemistry
Topic: Faraday's Laws