The kinetic energy of a simple harmonic oscillator is oscillating with angular frequency of 176 rad / s . The frequency of this simple harmonic oscillator is Hz. [ . take .π=22/7 ]

Physics · Simple Harmonic Motion

JEE Main 2026 — 21 January, Evening Shift — Question 32

The kinetic energy of a simple harmonic oscillator is oscillating with angular frequency of $176 \mathrm{rad} / \mathrm{s}$ . The frequency of this simple harmonic oscillator is Hz. $\left[\right.$ take $\left.\pi=\frac{22}{7}\right]$

Option A:
14
Correct
Option B:
88
Option C:
28
Option D:
176

Answer: A

Step-by-step solution

$\boldsymbol{\omega}=176 \mathrm{rad} / \mathrm{sec}$ $\mathrm{f}_{\mathrm{k}}=\frac{\omega}{2 \pi}=\frac{176}{2 \times 22} \times 7$ $=\frac{176}{44} \times 7$ $=4 \times 7=28 \mathrm{~Hz}$ So frequency of oscillator $=\frac{\mathrm{f}_{\mathrm{k}}}{2}=14 \mathrm{~Hz}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 21 January, Evening Shift
Subject: Physics
Chapter: Simple Harmonic Motion
Topic: Kinematics of SHM, Phase and Energy in SHM