Start free

Physics · Current Electricity

JEE Main 2026 — 21 January, Morning Shift — Question 44

The heat generated in 1 minute between points A and B in the given circuit, when a battery of 9 V with internal resistance of 1Ω1 \Omega is connected across these points is ____\_\_\_\_ J.

Question figure

Answer: 1080

Numerical answer — enter this value.

Step-by-step solution

i=93=3 A∴HAB=i2RABt=(3)2×2×60=1080 J\begin{aligned} \mathrm{i}=\frac{9}{3} & =3 \mathrm{~A} \therefore \quad \mathrm{H}_{\mathrm{AB}} & =\mathrm{i}^{2} \mathrm{R}_{\mathrm{AB}} \mathrm{t} & =(3)^{2} \times 2 \times 60=1080 \mathrm{~J} \end{aligned}
Solution figure

Answer key and solution verified before publishing.

Practise Current Electricity

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free
Exam
JEE Main 2026
Paper
21 January, Morning Shift
Subject
Physics
Chapter
Current Electricity
Topic
Circuit Analysis, Kirchhoff's Law and Nodal Analysis
The heat generated in 1 minute between points A and B in the given… | JEE Main 2026 PYQ with Solution · DhiX AI