Physics · Thermodynamics

JEE Main 2024 — 5 April, Shift 1 — Question 46

The heat absorbed by a system in going through the given cyclic process is :

Answer: A

$\Delta \mathrm{U}=0$ (Cyclic process)

$\Delta \mathrm{Q}=\mathrm{W}=$ area of $\mathrm{P}-\mathrm{V}$ curve.

$=\pi \times\left(140 \times 10^{3} \mathrm{~Pa}\right) \times\left(140 \times 10^{-6} \mathrm{~m}^{3}\right)$

$\Delta \mathrm{Q}=61.6 \mathrm{~J}$

Answer key and solution verified before publishing.

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