Physics · Current Electricity

JEE Main 2026 — 28 January, Morning Shift — Question 43

The equivalent resistance between the points $A$ and $B$ in the following circuit is $\frac{x}{5} \Omega$ . The value of $x$ is $\_\_\_\_$ .

Question figure

Answer: 21

Numerical answer — enter this value.

Step-by-step solution

6 i_1 + 3(2 i_1 - i) &= 3(i - i_1) \\ &\Rightarrow 15 i_1 = 6 i \quad \Rightarrow \quad i_1 = \frac{2}{5} i \\[1em] 3(i - i_1) + 6 i_1 &= 1 \\ 3 i + 3 i_1 &= 1 \\ \left(3 + \frac{6}{5}\right) i &= 1 \\ &\Rightarrow i = \frac{5}{21} \, \mathrm{A} = \frac{1 \, \mathrm{V}}{R_\text{eq}} \quad \Rightarrow \quad R_\text{eq} = \frac{21}{5} \, \Omega \end{aligned}$$

Solution figure

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Exam: JEE Main 2026
Paper: 28 January, Morning Shift
Subject: Physics
Chapter: Current Electricity
Topic: Combination of Resistors and cells, Wheatstone Bridge

The equivalent resistance between the points A and B in the following… | JEE Main 2026 PYQ with Solution · DhiX AI