JEE Main 2026 — 23 January, Morning Shift — Question 45

Here, $\mathrm{v}=\frac{\omega}{\mathrm{K}}=\frac{6.27 \times 10^{3}}{2.09 \times 10^{-5}}$ $=3 \times 10^{8}$ So, wave moving in vacuum Now, $I=\left(\frac{1}{2} \varepsilon_{0} E_{0}^{2}\right) c=\frac{1}{2} \varepsilon_{0} E_{0}^{2} \frac{1}{\sqrt{\mu_{0} \varepsilon_{0}}}$ $=\frac{1}{2} \sqrt{\frac{\varepsilon_{0}}{\mu_{0}}} \mathrm{E}_{0}^{2}=\frac{1}{2} \frac{1}{377} \times 377$ $\frac{1}{\mathrm{~d}}=\frac{1}{2}$ $\mathrm{d}=2$