Physics · Transverse waves

JEE Main 2025 — 7 April, Evening Shift — Question 63

The equation of a wave travelling on a string is $y=\sin$ $[20 \pi x+10 \pi t]$ , where $x$ and $t$ are distance

and time in SI units. The minimum distance between two points having the same oscillating speed is :

Answer: D

$k=20 \pi=\frac{2 \pi}{\lambda}$ $\lambda=10 \mathrm{~cm}$ Minimum distance

$=\frac{\lambda}{2}=5 \mathrm{~cm}$

Answer key and solution verified before publishing.

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