The electrostatic force (overrightarrow F 1 ) and magnetic force (overrightarrow F 2 ) acting on a charge q moving with velocity v can be written :

vec F 1 = q overrightarrow E , overrightarrow F 2 = q (overrightarrow V × overrightarrow B )

overrightarrow F 1 = q overrightarrow V × overrightarrow E , overrightarrow F 2 = q (overrightarrow B × overrightarrow V )

overrightarrow F 1 = q overrightarrow B , overrightarrow F 2 = q (overrightarrow B × overrightarrow V )

overrightarrow F 1 = q overrightarrow E , overrightarrow F 2 = q (overrightarrow B × overrightarrow V )

Physics · Moving Charges and Magnetic Field

JEE Main 2024 — 5 April, Shift 2 — Question 38

The electrostatic force $\left(\overrightarrow{\mathrm{F}}_{1}\right)$ and magnetic force $\left(\overrightarrow{\mathrm{F}}_{2}\right)$ acting on a charge q moving with velocity v can be written :

Option A:
$\overrightarrow{\mathrm{F}}_{1}=\mathrm{q} \overrightarrow{\mathrm{V}} \cdot \overrightarrow{\mathrm{E}}, \overrightarrow{\mathrm{F}}_{2}=\mathrm{q}(\overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{V}})$
Option B:
$\overrightarrow{\mathrm{F}}_{1}=\mathrm{q} \overrightarrow{\mathrm{B}}, \overrightarrow{\mathrm{F}}_{2}=\mathrm{q}(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{V}})$
Option C:
$\vec{F}_{1}=\mathrm{q} \overrightarrow{\mathrm{E}}, \overrightarrow{\mathrm{F}}_{2}=\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})$
Correct
Option D:
$\overrightarrow{\mathrm{F}}_{1}=\mathrm{q} \overrightarrow{\mathrm{E}}, \overrightarrow{\mathrm{F}}_{2}=\mathrm{q}(\overrightarrow{\mathrm{B}} \times \overrightarrow{\mathrm{V}})$

Answer: C

Step-by-step solution

$\quad \overrightarrow{\mathrm{F}}_{1}=\mathrm{q} \overrightarrow{\mathrm{E}} \quad$ (Theory)

$\overrightarrow{\mathrm{F}}_{2}=\mathrm{q}(\overrightarrow{\mathrm{V}} \times \overrightarrow{\mathrm{B}})$

Answer key and solution verified before publishing.

Practise Moving Charges and Magnetic Field

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Solve a similar one free

Exam: JEE Main 2024
Paper: 5 April, Shift 2
Subject: Physics
Chapter: Moving Charges and Magnetic Field
Topic: Motion of Charged Particles in Combined Electric and Magnetic Fields

A solenoid of length 0.5 m has a radius of 1 cm and is made up of ' m ' number of turns. It carries a current of 5 A . If the magnitude of…

Answer: C

Step-by-step solution

Practise Moving Charges and Magnetic Field

More Moving Charges and Magnetic Field questions from this paper