Physics · Electromagnetic Waves

JEE Main 2026 — 21 January, Morning Shift — Question 34

The electric field a plane electromagnetic wave is given by : Ey=69sin⁡[0.6×103x−1.8×1011t]V/m\mathrm{E}_{\mathrm{y}}=69 \sin \left[0.6 \times 10^{3} \mathrm{x}-1.8 \times 10^{11} \mathrm{t}\right] \mathrm{V} / \mathrm{m}. The expression for magnetic field associated with this electromagnetic wave is ____\_\_\_\_ T.

  1. Option A:

    Bz=2.3×10−7sin⁡[0.6×103x−1.8×1011t]\mathrm{B}_{\mathrm{z}}=2.3 \times 10^{-7} \sin \left[0.6 \times 10^{3} \mathrm{x}-1.8 \times 10^{11} \mathrm{t}\right]

    Correct
  2. Option B:

    Bz=2.3×10−7sin⁡[0.6×103x+1.8×1011t]\mathrm{B}_{\mathrm{z}}=2.3 \times 10^{-7} \sin \left[0.6 \times 10^{3} \mathrm{x}+1.8 \times 10^{11} \mathrm{t}\right]

  3. Option C:

    By=69sin⁡[0.6×103x+1.8×1011t]\mathrm{B}_{\mathrm{y}}=69 \sin \left[0.6 \times 10^{3} \mathrm{x}+1.8 \times 10^{11} \mathrm{t}\right]

  4. Option D:

    By=2.3×10−7sin⁡[0.6×103x−1.8×1011t]\mathrm{B}_{\mathrm{y}}=2.3 \times 10^{-7} \sin \left[0.6 \times 10^{3} \mathrm{x}-1.8 \times 10^{11} \mathrm{t}\right]

Answer: A

Step-by-step solution

B^=c^×E^\hat{B}=\hat{c} \times \hat{E} ⇒c^=i^\Rightarrow \quad \hat{\mathrm{c}}=\hat{\mathrm{i}} because phase of electric field is function of x .

⇒E^=j^ (given) ⇒B^=i^×j^=k^∣ B∣=∣E∣c=69×0.6×1031.8×1011=693×108∣ B∣=2.9×10−7 B→2=2.9×10−7sin⁡(0.6×103x−1.8×1011t)\begin{aligned} \Rightarrow \quad & \hat{\mathrm{E}}=\hat{\mathrm{j}} \text { (given) } \Rightarrow \quad & \hat{\mathrm{B}}=\hat{\mathrm{i}} \times \hat{\mathrm{j}}=\hat{\mathrm{k}} & |\mathrm{~B}|=\frac{|\mathrm{E}|}{\mathrm{c}}=\frac{69 \times 0.6 \times 10^{3}}{1.8 \times 10^{11}}=\frac{69}{3 \times 10^{8}} & |\mathrm{~B}|=2.9 \times 10^{-7} & \overrightarrow{\mathrm{~B}}_{2}=2.9 \times 10^{-7} \sin \left(0.6 \times 10^{3} \mathrm{x}-1.8 \times 10^{11} \mathrm{t}\right) \end{aligned}

(phase is same as that of electric field)

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Physics
Chapter
Electromagnetic Waves
Topic
Displacement Current and Equation of EM Waves