JEE Main 2024 — 31 January, Shift 2 — Question 54

The distance between charges +q and -q is $2 l$ and between +2 q and -2 q is $4 l$. The electrostatic potential at point P at a distance r from centre O is $-\alpha\left[\frac{q l}{r^{2}}\right] \times 10^{9} V, \quad$ where the value of $\alpha$ is $\_\_\_\_\_\_\_\_\_\_$ (Use $\frac{1}{4 \pi \varepsilon_{0}}=9 \times 10^{9} \mathrm{Nm}^{2} \mathrm{C}^{-2}$ )