Physics · Current Electricity

JEE Main 2024 — 29 January, Shift 1 — Question 42

The deflection in moving coil galvanometer falls from 25 divisions to 5 division when a shunt of 24Ω24 \Omega is applied. The resistance of galvanometer coil will be :

  1. Option A:

    12Ω12 \Omega

  2. Option B:

    96Ω96 \Omega

    Correct
  3. Option C:

    48Ω48 \Omega

  4. Option D:

    100Ω100 \Omega

Answer: B

Step-by-step solution

Let x=\mathrm{x}= current/division

figure

After applying shunt Now

figure

5x×G=20x×245 \mathrm{x} \times \mathrm{G}=20 \mathrm{x} \times 24

G=4×24\mathrm{G}=4 \times 24

G=96Ω\mathrm{G}=96 \Omega

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Physics
Chapter
Current Electricity
Topic
Electrical Measuring Instruments
The deflection in moving coil galvanometer falls from 25 divisions to… | JEE Main 2024 PYQ with Solution · DhiX AI