The crystal field splitting energy of [ Co ( oxalate ) 3 ] 3- complex is ' n ' times that of the .[ Cr (oxalate) ) 3 ] 3- complex. Here ' n ' is \ \ \ \ . [Assume Δ 0 gg P ]

Chemistry · Coordination Compounds

JEE Main 2026 — 23 January, Morning Shift — Question 70

The crystal field splitting energy of $\left[\mathrm{Co}(\text { oxalate })_{3}\right]^{3-}$ complex is ' n ' times that of the $\left.[\mathrm{Cr} \text { (oxalate) })_{3}\right]^{3-}$ complex. Here ' n ' is $\_\_\_\_$ . [Assume $\Delta_{0} \gg \mathrm{P}$ ]

Answer: 2

Numerical answer — enter this value.

Step-by-step solution

Pairing energy neglected w.r.t. $\Delta_{0}$ $\left[\mathrm{Co}(\mathrm{ox})_{3}\right]^{3-}: \mathrm{Co}^{+3}: \mathrm{d}^{6} ; \mathrm{t}_{2} \mathrm{~g}^{2,2,2} \mathrm{eg}^{0,0}$ $\mathrm{CFSE}=6 \times\left(-0.4 \Delta_{0}\right)=-2.4 \Delta_{0}$ $\left[\mathrm{Cr}\left(\mathrm{ox}_{3}\right)\right]^{3-}: \mathrm{Cr}^{+3}: \mathrm{d}^{3} ; \mathrm{t}_{2} \mathrm{~g}^{1,1,1} \mathrm{eg}^{0,0}$ CFSE $=3 \times\left(-0.4 \Delta_{0}\right)=-1.2 \Delta_{0}$ $\frac{(\mathrm{CFSE})_{\mathrm{Co}^{+3}}}{(\mathrm{CFSE})_{\mathrm{Cr}^{+3}}}=2$

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Exam: JEE Main 2026
Paper: 23 January, Morning Shift
Subject: Chemistry
Chapter: Coordination Compounds
Topic: Theories of Bonding in Coordination Compounds

Answer: 2

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