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Physics · Semiconductor and Electronic Devices

JEE Main 2024 — 6 April, Shift 1 — Question 43

The correct truth table for the following logic circuit is :

Question figure
  1. Option A:
    Option A figure
  2. Option B:
    Option B figure
    Correct
  3. Option C:
    Option C figure
  4. Option D:
    Option D figure

Answer: B

Step-by-step solution

Given logic circuit

The left gate is an OR gate, so its output is (A + B). The upper branch contains a NOT gate, giving output A. Both outputs are applied to the final OR gate.

Boolean expression:

Y=(A+B)+A‾Y = (A + B) + \overline{A}

Simplification:

Y=A+A‾+B=1+B=1Y = A + \overline{A} + B = 1 + B = 1

Truth table:

A & B & Y \\ \hline 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 1 \end{array}$$ Correct option = B
Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
6 April, Shift 1
Subject
Physics
Chapter
Semiconductor and Electronic Devices
Topic
Boolean Algebra, Truth Tables and Logic Gates
The correct truth table for the following logic circuit is : | JEE Main 2024 PYQ with Solution · DhiX AI