Chemistry · Coordination Compounds

JEE Main 2024 — 9 April, Shift 2 — Question 61

The coordination environment of $\mathrm{Ca}^{2+}$ ion in its complex with EDTA $^{4}$ is :

Option A:
tetrahedral
Option B:
octahedral
Correct
Option C:
square planar
Option D:
trigonal prismatic

Answer: B

Step-by-step solution

EDTA ${ }^{4-} \rightarrow$ Hexadentate ligand

$[\mathrm{Ca}(\text { EDTA })]^{2-}$

So Coordination environment is octahedral

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 9 April, Shift 2
Subject: Chemistry
Chapter: Coordination Compounds
Topic: Isomerism in Coordination Compounds

Match List I with List II LIST-I LIST-II --- --- --- --- A. K 2 [ Ni( CN) 4 ] I. sp ^3 B. [ Ni( CO) 4 ] II. sp ^3 d^2 C. [ C o^2 ( N H 3 )…

The coordination environment of Ca 2+ ion in its complex with EDTA 4… | JEE Main 2024 PYQ with Solution · DhiX AI