Physics · Capacitors and R-C Circuits

JEE Main 2026 — 21 January, Evening Shift — Question 27

The charge stored by the capacitor C in the given circuit in the steady state is $\_\_\_\_$ $\mu \mathrm{C}$ .

Answer: B

in steady state $\mathrm{i}=2.5 / 5=0.5 \mathrm{~A}$ $\mathrm{V}_{\mathrm{C}}=4 \times 0.5$ $\mathrm{V}_{\mathrm{c}}=2 \mathrm{~V}$ charge

\begin{aligned} \mathrm{Q} & =\mathrm{CV}_{\mathrm{c}} & =5 \times 2 & =10 \mu \mathrm{C} \end{aligned}

Answer key and solution verified before publishing.

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