Mathematics · Area under the Curves

JEE Main 2025 — 28 January, Morning Shift — Question 20

The area (in sq. units) of the region {(x,y):0≤y≤2∣x∣+1,0≤y≤x2+1,∣x∣≤3}\left\{(\mathrm{x}, \mathrm{y}): 0 \leq \mathrm{y} \leq 2|\mathrm{x}|+1,0 \leq \mathrm{y} \leq \mathrm{x}^{2}+1,|\mathrm{x}| \leq 3\right\} is

  1. Option A:

    803\frac{80}{3}

  2. Option B:

    643\frac{64}{3}

    Correct
  3. Option C:

    173\frac{17}{3}

  4. Option D:

    323\frac{32}{3}

Answer: B

Step-by-step solution

Area =2[∫02(x2+1)dx+∫23(2x+1)dx]=2\left[\int_{0}^{2}\left(x^{2}+1\right) d x+\int_{2}^{3}(2 x+1) d x\right]

⇒643\Rightarrow \frac{64}{3}

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Mathematics
Chapter
Area under the Curves
Topic
Area under the Curves
The area (in sq. units) of the region \ ( x , y ): 0 leq y leq 2 x… | JEE Main 2025 PYQ with Solution · DhiX AI