Physics · Motion in Plane

JEE Main 2024 — 8 April, Shift 2 — Question 38

The angle of projection for a projectile to have same horizontal range and maximum height is :

Option A:
$\tan ^{-1}(2)$
Option B:
$\tan ^{-1}(4)$
Correct
Option C:
$\tan ^{-1}\left(\frac{1}{4}\right)$
Option D:
$\tan ^{-1}\left(\frac{1}{2}\right)$

Answer: B

Step-by-step solution

$\frac{u^{2} \sin 2 \theta}{g}=\frac{u^{2} \sin ^{2} \theta}{2 g}$

$4 \sin \theta \cos \theta=\sin ^{2} \theta$

$4=\tan \theta$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 8 April, Shift 2
Subject: Physics
Chapter: Motion in Plane
Topic: Oblique and Horizontal Projectile Motion

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