JEE Main 2026 — 8 April, Evening Shift — Question 63

$\mathrm{CaCO}_{3}(\mathrm{~s}) \rightleftharpoons \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g}), \mathrm{K}_{\mathrm{P}_{1}}=0.08 \mathrm{~atm} \mathrm{K}_{\mathrm{P}_{1}}=\mathrm{P}_{\mathrm{CO}_{2}}=0.08 \mathrm{~atm}$ $\mathrm{C}(\mathrm{s})+\mathrm{CO}_{2}(\mathrm{~g}) \rightleftharpoons 2 \mathrm{CO}(\mathrm{g}), \mathrm{K}_{\mathrm{P}_{2}}=2$ $\mathrm{K}_{\mathrm{P}_{2}}=\frac{\mathrm{P}_{\mathrm{CO}}^{2}}{\mathrm{P}_{\mathrm{CO}_{2}}}=2$ $\frac{\mathrm{P}_{\mathrm{CO}}^{2}}{0.08}=2$ $\mathrm{P}_{\mathrm{CO}}^{2}=16 \times 10^{-2}$ $\mathrm{P}_{\mathrm{CO}}=4 \times 10^{-1}$