RMgI when treated with ice cold water liberated a gas which occupied 1.4 dm 3 / g at STP. The gas produced is further reacted with iodine in presence of HIO 3 to give compound (X). Compound (X) in presence of Na and dry ether produced compound ( Y ) . Molar mass of compound ( Y ) is \ \ \ \ g mol -1 . (Nearest integer)

Chemistry · Alkyl and Aryl Halides

JEE Main 2026 — 5 April, Evening Shift — Question 67

RMgI when treated with ice cold water liberated a gas which occupied $1.4 \mathrm{dm}^{3} / \mathrm{g}$ at STP. The gas produced is further reacted with iodine in presence of $\mathrm{HIO}_{3}$ to give compound (X). Compound (X) in presence of Na and dry ether produced compound $(\mathrm{Y})$ . Molar mass of compound $(\mathrm{Y})$ is $\_\_\_\_$ $\mathrm{g} \mathrm{mol}^{-1}$ . (Nearest integer)

Answer: 30

Numerical answer — enter this value.

Step-by-step solution

$=1.4 \mathrm{dm}^{3} / \mathrm{gm}$ at STP Hence according to this mol. Mass of gas is $=16$ Hence liberated gas is $=\mathrm{CH}_{4}$ (Methane) $\mathrm{CH}_{4}+\mathrm{I}_{2} \xrightarrow{\mathrm{HIO}_{3}} \mathrm{CH}_{3}-\mathrm{I}+\mathrm{HI}$ X Molar mass $=30$

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Exam: JEE Main 2026
Paper: 5 April, Evening Shift
Subject: Chemistry
Chapter: Alkyl and Aryl Halides
Topic: Introduction to Alkyl Halides and Methods of Preparation