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Physics · Alternating Current

JEE Main 2024 — 30 January, Shift 1 — Question 37

Primary coil of a transformer is connected to 220 V ac. Primary and secondary turns of the transforms are 100 and 10 respectively. Secondary coil of transformer is connected to two series resistance shown in shown in figure. The output voltage (V0)\left(\mathrm{V}_{0}\right) is :

Question figure
  1. Option A:

    7 V

    Correct
  2. Option B:

    15 V

  3. Option C:

    44 V

  4. Option D:

    22 V

Answer: A

Step-by-step solution

ε1ε2=N1N2=10010⇒ε2=22 V\frac{\varepsilon_{1}}{\varepsilon_{2}}=\frac{N_{1}}{N_{2}}=\frac{100}{10} \Rightarrow \varepsilon_{2}=22 \mathrm{~V} I=2222×103=1 mA,V0=7 VI=\frac{22}{22 \times 10^{3}}=1 \mathrm{~mA}, V_{0}=7 \mathrm{~V}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
30 January, Shift 1
Subject
Physics
Chapter
Alternating Current
Topic
L-C Circuits oscillations and Quality Factor, Resonance

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