Chemistry · d and f Block Elements

JEE Main 2025 — 4 April, Morning Shift — Question 5

Pair of transition metal ions having the same number of unpaired electrons is

  1. Option A:

    V2+,Co2+\mathrm{V}^{2+}, \mathrm{Co}^{2+}

    Correct
  2. Option B:

    Ti2+,Co2+\mathrm{Ti}^{2+}, \mathrm{Co}^{2+}

  3. Option C:

    Fe3+,Cr2+\mathrm{Fe}^{3+}, \mathrm{Cr}^{2+}

  4. Option D:

    Ti3+,Mn2+\mathrm{Ti}^{3+}, \mathrm{Mn}^{2+}

Answer: A

Step-by-step solution

V2+  ⟹  3d34s0  ⟹  [↑↓][↑][ ][ ][ ]  ⟹  3 unpaired e−\text{V}^{2+} \implies 3d^3 4s^0 \implies [\uparrow \downarrow] [\uparrow] [\ ] [\ ] [\ ] \implies 3 \text{ unpaired } e^- Co2+  ⟹  3d74s0  ⟹  [↑↓][↑↓][↑][↑][↑]  ⟹  3 unpaired e−\text{Co}^{2+} \implies 3d^7 4s^0 \implies [\uparrow \downarrow] [\uparrow \downarrow] [\uparrow] [\uparrow] [\uparrow] \implies 3 \text{ unpaired } e^- Ti2+  ⟹  3d24s0  ⟹  [↑][↑][ ][ ][ ]  ⟹  2 unpaired e−\text{Ti}^{2+} \implies 3d^2 4s^0 \implies [\uparrow] [\uparrow] [\ ] [\ ] [\ ] \implies 2 \text{ unpaired } e^- Fe3+  ⟹  3d54s0  ⟹  [↑][↑][↑][↑][↑]  ⟹  5 unpaired e−\text{Fe}^{3+} \implies 3d^5 4s^0 \implies [\uparrow] [\uparrow] [\uparrow] [\uparrow] [\uparrow] \implies 5 \text{ unpaired } e^- Cr2+  ⟹  3d44s0  ⟹  [↑][↑][↑][↑][ ]  ⟹  4 unpaired e−\text{Cr}^{2+} \implies 3d^4 4s^0 \implies [\uparrow] [\uparrow] [\uparrow] [\uparrow] [\ ] \implies 4 \text{ unpaired } e^- Ti3+  ⟹  3d14s0  ⟹  [↑][ ][ ][ ][ ]  ⟹  1 unpaired e−\text{Ti}^{3+} \implies 3d^1 4s^0 \implies [\uparrow] [\ ] [\ ] [\ ] [\ ] \implies 1 \text{ unpaired } e^- Mn2+  ⟹  3d54s0  ⟹  [↑][↑][↑][↑][↑]  ⟹  5 unpaired e−\text{Mn}^{2+} \implies 3d^5 4s^0 \implies [\uparrow] [\uparrow] [\uparrow] [\uparrow] [\uparrow] \implies 5 \text{ unpaired } e^-

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Chemistry
Chapter
d and f Block Elements
Topic
Properties of compounds of 3d Series elements + Comparison between 3d, 4d, 5d
Pair of transition metal ions having the same number of unpaired… | JEE Main 2025 PYQ with Solution · DhiX AI