One mole of PbS is oxidised by X moles of O 3 to form Y moles of O 2 . Find the value of X+Y .

Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

JEE Main 2024 — 27 January, Shift 2 — Question 81

One mole of $\mathrm{PbS}$ is oxidised by $X$ moles of $\mathrm{O_3}$ to form $Y$ moles of $\mathrm{O_2}$ . Find the value of $X+Y$ .

Numerical answer — enter this value.

Oxidation of lead sulphide: $\mathrm{PbS + 4O_3 \rightarrow PbSO_4 + 4O_2}$

From the balanced equation, $1\,\mathrm{mol\ PbS} \text{\; reacts\; with\; } 4\,\mathrm{mol\ O_3}$ and $4\,\mathrm{mol\ O_2}$ are formed.

Hence,

X = 4,\quad Y = 4

X + Y = 8

Answer key and solution verified before publishing.

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