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Physics · Thermal Properties of Matter

JEE Main 2024 — 4 April, Shift 1 — Question 38

On celcius scale the temperature of body increases by 40∘C40^{\circ} \mathrm{C}. The increase in temperature on Fahrenheit scale is:

  1. Option A:

    70∘F70^{\circ} \mathrm{F}

  2. Option B:

    68∘F68^{\circ} \mathrm{F}

  3. Option C:

    72∘F72^{\circ} \mathrm{F}

    Correct
  4. Option D:

    75∘F75^{\circ} \mathrm{F}

Answer: C

Step-by-step solution

We know that per ∘C{ }^{\circ} \mathrm{C} change is equivalent to 1.8∘1.8^{\circ} change in ∘F{ }^{\circ} \mathrm{F}.

∴40∘\therefore 40^{\circ} change on celcius scale will corresponds to 72∘72^{\circ} change on Fahrenheit scale.

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
4 April, Shift 1
Subject
Physics
Chapter
Thermal Properties of Matter
Topic
Thermometry and Calorimetry

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