Chemistry · Nitrogen Containing Organic Compounds

JEE Main 2024 — 5 April, Shift 1 — Question 84

$9.3 \mathrm{~g}$ of pure aniline is treated with bromine water at room temperature to give a white precipitate of the product ' P '. The mass of product ' P ' obtained is 26.4 g . The percentage yield is $\qquad$ $\%$ .

Answer: 80

Numerical answer — enter this value.

Step-by-step solution

93 g of aniline produces 330 g of 2, 4, 6tribromoaniline. Hence 9.3 g of aniline should produce 33 g of 2, 4, 6 -tribromoaniline.

Hence percentage yield $\frac{26.4\times 100}{33}=80\text{ }\!\!%\!\!\text{ }$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 5 April, Shift 1
Subject: Chemistry
Chapter: Nitrogen Containing Organic Compounds
Topic: Aniline