Number of moles and number of molecules in 1.4187 L of SO 2 at STP respectively are

Chemistry · Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry

JEE Main 2026 — 4 April, Morning Shift — Question 48

Number of moles and number of molecules in 1.4187 L of $\mathrm{SO}_{2}$ at STP respectively are

Option A:
$0.1266 ; 3.812 \times 10^{22}$
Option B:
$0.0633 ; 3.812 \times 10^{22}$
Correct
Option C:
$0.1266 ; 7.6238 \times 10^{22}$
Option D:
$0.0633 ; 7.6238 \times 10^{22}$

Answer: B

Step-by-step solution

$\quad$ moles $=\frac{\mathrm{V} \text { lit }}{22.7 \text { lit }} \Rightarrow \frac{1.4187 \text { lit }}{22.7 \text { lit }} \Rightarrow 0.0633$ no. of molecules $=$ moles $\times 6.023 \times 10^{23}$ $\Rightarrow 0.0633 \times 6.032 \times 10^{3}$ $=3.812 \times 10^{22}$

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Exam: JEE Main 2026
Paper: 4 April, Morning Shift
Subject: Chemistry
Chapter: Some Basic Concepts of Chemistry (Mole Concept) + Stoichiometry
Topic: Introduction to Mole Concept