Physics · Fluid Mechanics

JEE Main 2024 — 4 April, Shift 2 — Question 59

Mercury is filled in a tube of radius 2 cm up to a height of 30 cm . The force exerted by mercury on the bottom of the tube

is ___ N. (Given, atmospheric pressure $=10^{5} \mathrm{Nm}^{-2}$ , density of mercury $=1.36 \times 10^{4} \mathrm{~kg} \mathrm{~m}^{-3}, \mathrm{~g}=10 \mathrm{~ms}^{-2}$ ,

$\left.\pi=\frac{22}{7}\right)$

Answer: 177

Numerical answer — enter this value.

Step-by-step solution

$\quad \mathrm{F}=\mathrm{P}_{0} \mathrm{~A}+\rho_{\mathrm{m}}$ ghA $=10^{5} \times \frac{22}{7} \times\left(2 \times 10^{-2}\right)^{2}$

$+1.36 \times 10^{4} \times 10 \times\left(30 \times 10^{-2}\right)\left(\frac{22}{7} \times\left(2 \times 10^{-2}\right)^{2}\right)$

$\mathrm{F}=51.29+125.71=177 \mathrm{~N}$

Answer key and solution verified before publishing.

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Exam: JEE Main 2024
Paper: 4 April, Shift 2
Subject: Physics
Chapter: Fluid Mechanics
Topic: Force Exerted by Liquids on Walls of a Container