Match the List-I with List-II List-I Electronic configuration of tetrahedral metal ion List-II Crystal Field Stabilization Energy (Δ t ) --- --- A. d 2 I. –0.6 B. d 4 II. –0.8 C. d 6 III. –1.2 D. d 8 IV. –0.4 Choose the correct answer from the options given below :

Chemistry · Coordination Compounds

JEE Main 2026 — 6 April, Morning Shift — Question 55

Match the List-I with List-II

List-I Electronic configuration of tetrahedral metal ion	List-II Crystal Field Stabilization Energy $\left(\Delta_{\mathbf{t}}\right)$
A. $d^2$	I. –0.6
B. $d^4$	II. –0.8
C. $d^6$	III. –1.2
D. $d^8$	IV. –0.4

Choose the correct answer from the options given below :

In tetrahedral complex

\begin{aligned} \text{CFSE} &= \left[-\frac{3}{5}n_1+\frac{2}{5}n_2\right]\Delta_t \\[4pt] d^2 &: \underbrace{e^{1,1}}_{n_1=2}\underbrace{t^{0,0,0}}_{n_2=0} \\ \text{C.F.S.E} &= \left[-\frac{3}{5}\right]\Delta_t=-1.2\Delta_t \\[4pt] d^4 &: \underbrace{e^{1,1}}_{n_1=2}\underbrace{t^{1,1,0}}_{n_2=2} \\ \text{C.F.S.E} &= \left[-\frac{3}{5}+\frac{2}{5}\right]\Delta_t=-0.4\Delta_t \\[4pt] d^6 &: \underbrace{e^{2,1}}_{n_1=3}\underbrace{t^{1,1,1}}_{n_2=3} \\ \text{C.F.S.E} &= \left[-\frac{3}{5}+\frac{2}{5}\right]\Delta_t=-0.6\Delta_t \\[4pt] d^8 &: \underbrace{e^{2,2}}_{n_1=4}\underbrace{t^{2,1,1}}_{n_2=4} \\ \text{C.F.S.E} &= \left[-\frac{3}{5}+\frac{2}{5}\right]\Delta_t=-0.8\Delta_t \end{aligned}

$A-\mathrm{III},\quad B-\mathrm{IV},\quad C-\mathrm{I},\quad D-\mathrm{II}$

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