Chemistry · Coordination Compounds

JEE Main 2026 — 4 April, Morning Shift — Question 59

Match the List-I with List-II Choose the correct answer from the options given below:

List-I Complex ionList-II Calculated spin only magnetic moment (BM)
A. [Cr(H2O)6]2+[\mathrm{Cr}(\mathrm{H}_2\mathrm{O})_6]^{2+}I. 3.87
B. [Co(H2O)6]2+[\mathrm{Co}(\mathrm{H}_2\mathrm{O})_6]^{2+}II. 5.92
C. [Cu(H2O)6]2+[\mathrm{Cu}(\mathrm{H}_2\mathrm{O})_6]^{2+}III. 4.90
D. [Mn(H2O)6]2+[\mathrm{Mn}(\mathrm{H}_2\mathrm{O})_6]^{2+}IV. 1.73
  1. Option A:

    A-I, B-III, C-IV, D-II

  2. Option B:

    A-II, B-I, C-III, D-IV

  3. Option C:

    A-IV, B-II, C-I, D-III

  4. Option D:

    A-III, B-I, C-IV, D-II

    Correct

Answer: D

Step-by-step solution

[Cr(H2O)6]2+→4\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+} \rightarrow 4 unpaired e−\mathrm{e}^{-}; 4.90 BM(III) [Co(H2O)6]2+→0\left[\mathrm{Co}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+} \rightarrow 0 unpaired e−;3.87BM(I)\mathrm{e}^{-} ; 3.87 \mathrm{BM}(\mathrm{I}) [Cu(H2O)6]2+→1\left[\mathrm{Cu}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+} \rightarrow 1 unpaired e−;1.73BM(IV)\mathrm{e}^{-} ; 1.73 \mathrm{BM}(\mathrm{IV}) [Mn(H2O)6]2+→5\left[\mathrm{Mn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+} \rightarrow 5 unpaired e−\mathrm{e}^{-}; 5.92 BM(II)

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Chemistry
Chapter
Coordination Compounds
Topic
Properties and importance of Coordination Complexes
Match the List-I with List-II Choose the correct answer from the… | JEE Main 2026 PYQ with Solution · DhiX AI