Chemistry · Alcohols, Ethers and Phenols
JEE Main 2024 — 27 January, Shift 2 — Question 67
Match the List-I with List-II and choose the correct answer from the options given below:
| List I (Reaction) | List II (Reagent(s)) |
|---|---|
(A)   | (I) |
(B)  | (II) (i) NaOH (ii) |
(C)  | (III) (i) (ii) NaOH (iii) HCl |
(D)  | (IV) (i) NaOH (ii) (iii) HCl |
- Option A:
(A)-(IV), (B)-(I), (C)-(III), (D)-(II)
- Option B:
(A)-(II), (B)-(III), (C)-(I), (D)-(IV)
- Option C:
(A)-(II), (B)-(I), (C)-(III), (D)-(IV)
- Option D:Correct
(A)-(IV), (B)-(III), (C)-(I), (D)-(II)
Answer: D
Step-by-step solution
(A) Phenol is converted into o-hydroxybenzoic acid (salicylic acid); this occurs via the Kolbe-Schmitt reaction, which involves treatment with NaOH followed by CO and then HCl, hence it matches with (IV).
(B) Phenol is converted into o-hydroxybenzaldehyde (salicylaldehyde); this transformation takes place through the Reimer--Tiemann reaction using NaOH and CHCl followed by acidification, therefore it matches with (III).
(C) Phenol is oxidised to p-benzoquinone; such oxidation is carried out using NaCrO and HSO, so it corresponds to (I).
(D) Phenol is converted into anisole (methoxybenzene); this is achieved by Williamson ether synthesis involving NaOH followed by CHCl, hence it matches with (II).
Therefore, the correct matching is (A)-(IV), (B)-(III), (C)-(I), (D)-(II).
Answer key and solution verified before publishing.
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- Exam
- JEE Main 2024
- Paper
- 27 January, Shift 2
- Subject
- Chemistry
- Chapter
- Alcohols, Ethers and Phenols
- Topic
- Phenols