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Physics · Electromagnetic Waves

JEE Main 2024 — 29 January, Shift 1 — Question 38

Match List I with List II

List IList II
A.∮  B⃗⋅dl→=μ0ic+μ0ε0  dϕEdt\oint {\rm{\;\vec B}} \cdot \overrightarrow {{\rm{dl}}} = {\mu _0}{{\rm{i}}_{\rm{c}}} + {\mu _0}{\varepsilon _0}\frac{{{\rm{\;d}}{\phi _{\rm{E}}}}}{{{\rm{dt}}}}I.Gauss' law for electricity
B.∮  E⃗⋅dl→=dϕBdt\oint {\rm{\;\vec E}} \cdot \overrightarrow {{\rm{dl}}} = \frac{{{\rm{d}}{\phi _{\rm{B}}}}}{{{\rm{dt}}}}II.Gauss' law for magnetism
C.∮  E⃗⋅dA→=Qε0\oint {\rm{\;\vec E}} \cdot \overrightarrow {{\rm{dA}}} = \frac{{\rm{Q}}}{{{\varepsilon _0}}}III.Faraday law
D.∮  B⃗⋅dA→=0\oint {\rm{\;\vec B}} \cdot \overrightarrow {{\rm{dA}}} = 0IV.Ampere - Maxwell law

Chose the correct answer from the options given below

  1. Option A:

    A – I B – II C – IV D – III

  2. Option B:

    A – IV B – III C – I D – II

    Correct
  3. Option C:

    A – III B – IV C – II D – I

  4. Option D:

    A – II B – I C – III D – IV

Answer: B

Step-by-step solution

Ampere - Maxwell law →∮B→⋅dl→=μ0ic+μ0ε0 dϕEdt\rightarrow \oint \overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{dl}}=\mu_{0} \mathrm{i}_{\mathrm{c}}+\mu_{0} \varepsilon_{0} \frac{\mathrm{~d} \phi_{\mathrm{E}}}{\mathrm{dt}}

Faraday law →∮E→⋅dl→=dϕBdt\rightarrow \oint \overrightarrow{\mathrm{E}} \cdot \overrightarrow{\mathrm{dl}}=\frac{\mathrm{d} \phi_{\mathrm{B}}}{\mathrm{dt}}

Gauss' law for electricity →∮E→⋅dA→=Qε0\rightarrow \oint \overrightarrow{\mathrm{E}} \cdot \overrightarrow{\mathrm{dA}}=\frac{\mathrm{Q}}{\varepsilon_{0}}

Gauss ' law for magnetism →∮B→⋅dA→=0\rightarrow \oint \overrightarrow{\mathrm{B}} \cdot \overrightarrow{\mathrm{dA}}=0

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
29 January, Shift 1
Subject
Physics
Chapter
Electromagnetic Waves
Topic
Displacement Current and Equation of EM Waves
Match List I with List II List I List II --- --- --- --- A. oint rm… | JEE Main 2024 PYQ with Solution · DhiX AI