Match List-I with List-II. List-I List-II --- --- (A) Solution of chloroform and acetone (I) Minimum boiling azeotrope (B) Solution of ethanol and water (II) Dimerizes (C) Solution of benzene and toluene (III) Maximum boiling azeotrope (D) Solution of acetic acid in benzene (IV) Δ V mix =0 Choose the correct answer from the options given below.

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

(A)-(II), (B)-(I), (C)-(IV), (D)-(III)

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

Chemistry · Solutions and Colligative Properties

JEE Main 2025 — 7 April, Evening Shift — Question 3

Match List-I with List-II.

List-I	List-II
(A) Solution of chloroform and acetone	(I) Minimum boiling azeotrope
(B) Solution of ethanol and water	(II) Dimerizes
(C) Solution of benzene and toluene	(III) Maximum boiling azeotrope
(D) Solution of acetic acid in benzene	(IV) $\Delta V_{mix}=0$

Choose the correct answer from the options given below.

Acetone + chloroform shows negative deviation and form maximum boiling point azeotrope. Ethanol and water

shows positive deviation and form minimum boiling point azeotrope. Benzene + toluene $\Rightarrow$ Ideal

solution Hence, $\Delta \mathrm{V}_{\text {mix }}=0$ Acetic acid will dimerise in benzene.

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