Physics · Units, Dimensions & Error Analysis

JEE Main 2026 — 5 April, Evening Shift — Question 1

Match List-I with List-II.

List-IList-II
(A) Meter (L)I. hcG\sqrt{\frac{hc}{G}}
(B) Second (S)II. Ghc5\sqrt{\frac{Gh}{c^5}}
(C) Kilogram (M)III. K2L2c5Gh\sqrt{\frac{K^2L^2c^5}{Gh}}
(D) Kelvin (K)IV. Ghc5\sqrt{\frac{Gh}{c^5}}

where h = Planck's constant, G = gravitational constant, c = speed of light in vacuum as fundamental units.

  1. Option A:

    A-II, B-IV, C-I, D-III

  2. Option B:

    A-IV, B-II, C-I, D-III

    Correct
  3. Option C:

    A-IV, B-I, C-II, D-III

  4. Option D:

    A-III, B-I, C-II, D-IV

Answer: B

Step-by-step solution

[h]=ML2T−1[h]=ML^2T^{-1}, [c]=LT−1[c]=LT^{-1}, [G]=M−1L3T−2[G]=M^{-1}L^3T^{-2}.

Then hc/G\sqrt{hc/G} gives [M], Gh/c5\sqrt{Gh/c^5} gives [T], K2L2c5/(Gh)\sqrt{K^2L^2c^5/(Gh)} gives [K], Gh/c5\sqrt{Gh/c^5} gives [L]

(note: IV appears twice? Actually II and IV are same expression, but solution maps A→IV, B→II, C→I, D→III).

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Units and Dimensions Analysis