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Physics · Gravitation

JEE Main 2024 — 5 April, Shift 1 — Question 42

Match list-I with list-II:

List-IList-II
(A)Kinetic energy of planet(I)−GMma-\frac{\text{GMm}}{\text{a}}
(B)Gravitation Potentialenergy of Sun-planet system.(III)GMm2a\frac{\text{GMm}}{2\text{a}}
(C)Total mechanical energyof planet(III)Gmr\frac{\text{Gm}}{\text{r}}
(D)Escape energy at thesurface of planet for unit mass object(IV)−GMm2a-\frac{\text{GMm}}{2\text{a}}

(Where a= radius of planet orbite, r=radius of planet, M=mass of sun, m=mass of planet)

Choose the correct answer from the options given below:

  1. Option A:

    (A) - II, (B) - I, (C) - IV, (D) - III

    Correct
  2. Option B:

    (A) - III, (B) - IV, (C) - I, (D) - II

  3. Option C:

    (A) - I, (B) - IV, (C) - II, (D) - III

  4. Option D:

    (A) - I, (B) - II, (C) - III, (D) - IV

Answer: A

Step-by-step solution

KE=12mv2=GMm2a\mathrm{KE}=\frac{1}{2} \mathrm{mv}^{2}=\frac{\mathrm{GMm}}{2 \mathrm{a}}

PE=−2KE\mathrm{PE}=-2 \mathrm{KE}

TE=−KE\mathrm{TE}=-\mathrm{KE}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Paper
5 April, Shift 1
Subject
Physics
Chapter
Gravitation
Topic
Gravitational Potential Energy and Potential
Match list-I with list-II: List-I List-II --- --- --- --- (A) Kinetic… | JEE Main 2024 PYQ with Solution · DhiX AI