Physics · Electromagnetic Waves

JEE Main 2024 — 5 April, Shift 2 — Question 43

Match List-I with List-II :-

List-I EM-WaveList-II Wavelength Range
(A)Infra-red(I)<10−3  ⁣ ⁣  ⁣ ⁣ nm<{{10}^{-3}}\text{ }\!\!~\!\!\text{ nm}
(B)Ultraviolet(II)400 nm to 1 nm
(C)X-rays(III)1 mm to 700 nm
(D)Gamma rays(IV)1 nm to 10−3  ⁣ ⁣  ⁣ ⁣ nm{{10}^{-3}}\text{ }\!\!~\!\!\text{ nm}

Choose the correct answer from the options given below :

  1. Option A:

    (A)-(II), (B)-(I), (C)-(IV), (D)-(III)

  2. Option B:

    (A)-(III), (B)-(II), (C)-(IV), (D)-(I)

    Correct
  3. Option C:

    (A)-(IV), (B)-(III), (C)-(II), (D)-(I)

  4. Option D:

    (A)-(I), (B)-(III), (C)-(II), (D)-(IV)

Answer: B

Step-by-step solution

Infrared is the least energetic thus having biggest wavelength (λ)(\lambda) & gamma rays are most energetic thus having smallest

wavelength (λ)(\lambda).

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Physics
Chapter
Electromagnetic Waves
Topic
Properties of EM Waves and Electromagnetic Spectrum
Match List-I with List-II :- List-I EM-Wave List-II Wavelength Range… | JEE Main 2024 PYQ with Solution · DhiX AI