Match List I with List II. List-I (Element) List-II (Electronic Configuration) --- --- --- --- A. N I. [ Ar ]\,3d 10 \,4s 2\,4p 5 B. S II. [ Ne ]\,3s 2\,3p 4 C. Br III. [ He ]\,2s 2\,2p 3 D Kr IV. [ Ar ]\,3d 10 \,4s 2\,4p 6 Choose the correct answer from the options given below:

Chemistry · Structure of Atom

JEE Main 2024 — 9 April, Shift 2 — Question 68

Match List I with List II.

List-I (Element)	List-II (Electronic Configuration)
A.	N	I.	$[\mathrm{Ar}]\,3d^{10}\,4s^2\,4p^5$
B.	S	II.	$[\mathrm{Ne}]\,3s^2\,3p^4$
C.	Br	III.	$[\mathrm{He}]\,2s^2\,2p^3$
D	Kr	IV.	$[\mathrm{Ar}]\,3d^{10}\,4s^2\,4p^6$

Choose the correct answer from the options given below:

Nitrogen $(Z=7)$ has configuration $1s^2\,2s^2\,2p^3 = [\mathrm{He}]\,2s^2\,2p^3$ . So, A → III

Sulphur $(Z=16)$ has configuration $[\mathrm{Ne}]\,3s^2\,3p^4$ . So, B → II

Bromine $(Z=35)$ has configuration $[\mathrm{Ar}]\,3d^{10}\,4s^2\,4p^5$ . So, C → I

Krypton $(Z=36)$ has configuration $[\mathrm{Ar}]\,3d^{10}\,4s^2\,4p^6$ . So, D → IV

Final matching is A-III, B-II, C-I, D-IV.

Answer key and solution verified before publishing.

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