Match List-I with List-II. List-I Electronic configuration of neutral atom (where n = 2) List-II 1st Ionization Energy (kJ mol –1 ) --- --- A. ns 2 I. 2080 B. n s 2 n p 1 II. 899 C. n s 2 n p 3 III. 800 D. n s 2 n p 6 IV. 1402 Choose the correct answer from the options given below :

Chemistry · Periodicity of Elements and Periodic Properties

JEE Main 2026 — 8 April, Evening Shift — Question 49

Match List-I with List-II.

List-I Electronic configuration of neutral atom (where n = 2)	List-II 1st Ionization Energy (kJ $mol^{–1}$ )
A. $\mathrm{ns}^{2}$	I. 2080
B. $n s^{2} n p^{1}$	II. 899
C. $n s^{2} n p^{3}$	III. 800
D. $n s^{2} n p^{6}$	IV. 1402

Choose the correct answer from the options given below :

Option A:
A-II, B-III, C-IV, D-I
Correct
Option B:
A-IV, B-III, C-II, D-I
Option C:
A-III, B-II, C-IV, D-I
Option D:
A-III, B-II, C-I, D-IV

Answer: A

Step-by-step solution

(A) $2 \mathrm{~s}^{2} \Rightarrow \mathrm{Be}$ (B) $2 \mathrm{~s}^{2} 2 \mathrm{p}^{1} \Rightarrow \mathrm{~B}$ (C) $2 s^{2} 2 p^{3} \Rightarrow \mathrm{~N}$ (D) $2 \mathrm{~s}^{2} 2 \mathrm{p}^{6} \Rightarrow \mathrm{Ne}$

IE order : $\mathrm{B}<\mathrm{Be}<\mathrm{N}<\mathrm{Ne}$ A-II, B-III, C-IV, D-I

Answer key and solution verified before publishing.

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Exam: JEE Main 2026
Paper: 8 April, Evening Shift
Subject: Chemistry
Chapter: Periodicity of Elements and Periodic Properties
Topic: Periodicity in Chemical Properties (Ionization Energy, Electron Affinity, Electronegativity)