Match List-I with List-II. Choose the correct answer from the options given below. List-I List-II --- --- (A) Isothermal (I) vartriangle W (work done) = 0 (B) Adiabatic (II) vartriangle Q (supplied heat) = 0 (C) Isobaric (III) vartriangle U (change in internal energy) ne 0 (D) Isochoric (IV) vartriangle U = 0

(A)-(IV), (B)-(II), (C)-(III), (D)-(I)

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

(A)-(IV), (B)-(I), (C)-(III), (D)-(II)

(A)-(III), (B)-(II), (C)-(I), (D)-(IV)

Physics · Thermodynamics

JEE Main 2025 — 7 April, Evening Shift — Question 57

Match List-I with List-II. Choose the correct answer from the options given below.

List-I	List-II
(A) Isothermal	(I) $\vartriangle$ W (work done) = 0
(B) Adiabatic	(II) $\vartriangle$ Q (supplied heat) = 0
(C) Isobaric	(III) $\vartriangle$ U (change in internal energy) $\ne$ 0
(D) Isochoric	(IV) $\vartriangle$ U = 0

For isothermal,

$T=$ constant, $\Delta T=0, \Delta U=n C_{v} \Delta T=0$

For Adiabatic, $\begin{gathered} \Delta Q=0, \Delta W=-\Delta U \end{gathered}$

For Isobaric, $p=$ constant, $\Delta U=n c, \Delta T \neq 0$ ,

\begin{gathered} \Delta Q \neq 0, \Delta W \neq 0 \end{gathered}

For Isochoric, $v=$ constant, $\Delta W=0, \Delta Q=\Delta U \neq 0$

Answer key and solution verified before publishing.

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