Physics · Units, Dimensions & Error Analysis

JEE Main 2025 — 2 April, Evening Shift — Question 53

Match List - I with List - II. Choose the correct answer from the options given below.

List - IList - II
(A) Heat capacity of body(I) Jkg−1\text{Jk}{{\text{g}}^{-1}}
(B) Specific heat capacity of body(II) Jk−1\text{J}{{\text{k}}^{-1}}
(C) Latent heat(III) Jkg−1  ⁣ ⁣  ⁣ ⁣ K−1\text{Jk}{{\text{g}}^{-1}}\text{ }\!\!~\!\!\text{ }{{\text{K}}^{-1}}
(D) Thermal conductivity(IV) Jm−1  ⁣ ⁣  ⁣ ⁣ K−1  ⁣ ⁣  ⁣ ⁣ s−1\text{J}{{\text{m}}^{-1}}\text{ }\!\!~\!\!\text{ }{{\text{K}}^{-1}}\text{ }\!\!~\!\!\text{ }{{\text{s}}^{-1}}
  1. Option A:

    (A)-(II), (B)-(III), (C)-(I), (D)-(IV)

    Correct
  2. Option B:

    (A)-(IV), (B)-(III), (C)-(II), (D)-(I)

  3. Option C:

    (A)-(III), (B)-(I), (C)-(II), (D)-(IV)

  4. Option D:

    (A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Answer: A

Step-by-step solution

Heat capacity =J/K,A→II=\mathrm{J} / \mathrm{K}, \quad \mathrm{A} \rightarrow \mathrm{II}

Specific heat capacity =J/kgK,B→III=\mathrm{J} / \mathrm{kg} \mathrm{K}, \quad B \rightarrow \mathrm{III}

Latent heat =J/kg,C→I=\mathrm{J} / \mathrm{kg}, \quad \mathrm{C} \rightarrow \mathrm{I}

Thermal conductivity k≡QAΔxΔT≡ J/mKs,D→IVk \equiv \frac{Q}{A} \frac{\Delta x}{\Delta T} \equiv \mathrm{~J} / \mathrm{mKs}, \quad \mathrm{D} \rightarrow \mathrm{IV}

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Physics
Chapter
Units, Dimensions & Error Analysis
Topic
Units and Dimensions Analysis
Match List - I with List - II. Choose the correct answer from the… | JEE Main 2025 PYQ with Solution · DhiX AI