Mathematics · Complex Numbers

JEE Main 2026 — 4 April, Evening Shift — Question 26

Let S={z∈C:z2+4z+16=0}S = \{z\in \mathbb{C}:z^2 +4z + 16 = 0\}. Then ∑z∈S∣z+3i∣2\sum_{z\in S}\left|z + \sqrt{3} i\right|^2 is equal to :

  1. Option A:

    42

  2. Option B:

    23

  3. Option C:

    27

  4. Option D:

    38

    Correct

Answer: D

Step-by-step solution

z2+4z+16=0z^{2}+4 z+16=0 ⇒(z+2)2=−12\Rightarrow(\mathrm{z}+2)^{2}=-12 ⇒z=−2±23i\Rightarrow \mathrm{z}=-2 \pm 2 \sqrt{3} \mathrm{i} ⇒S={−2+23i,−2−23i}\Rightarrow \mathrm{S}=\{-2+2 \sqrt{3} \mathrm{i},-2-2 \sqrt{3} \mathrm{i}\} ∴∑z∈S∣z+3i∣2\therefore \sum_{\mathrm{z} \in \mathrm{S}}|\mathrm{z}+\sqrt{3} \mathrm{i}|^{2} =∣−2+23i+3i∣2+∣−2−23i+3i∣2=|-2+2 \sqrt{3} i+\sqrt{3} i|^{2}+|-2-2 \sqrt{3} i+\sqrt{3} i|^{2} =∣−2+33i∣2+∣−2−3i∣2=|-2+3 \sqrt{3} \mathrm{i}|^{2}+|-2-\sqrt{3} \mathrm{i}|^{2} =38=38

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Mathematics
Chapter
Complex Numbers
Topic
Introduction to Complex Numbers
Let S = \ zin mathbb C :z 2 +4z + 16 = 0\ . Then sum zin S z + √(3) i… | JEE Main 2026 PYQ with Solution · DhiX AI