Mathematics · Statistics

JEE Main 2024 — 1 February, Shift 1 — Question 7

Let the median and the mean deviation about the median of 7 observation170,125,230,190,210,a,b170,125,230,190,210, a, b be 170 and 2057\frac{205}{7} respectively. Then the mean deviation about the mean of these 7 observations is :

  1. Option A:

    31

  2. Option B:

    28

  3. Option C:

    30

    Correct
  4. Option D:

    32

Answer: C

Step-by-step solution

Given observations: 170,125,230,190,210,a,b

Median = 170 ⇒ 4th term = 170

Arranging known values: 125,170,190,210,230

To keep median 170: a = 170

Given mean deviation about median = 205/7

So,

∑∣xi−170∣=205\sum |x_i -170| = 205 45+0+0+20+40+60+(170−b)=20545+0+0+20+40+60+(170-b)=205 165+170−b=205165+170-b=205 335−b=205335-b=205 b=130b=130

Mean:

xˉ=12257=175\bar{x}=\frac{1225}{7}=175

Mean deviation about mean:

50+45+5+5+15+35+557=2107=30\frac{50+45+5+5+15+35+55}{7} =\frac{210}{7} =30 30\boxed{30}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Statistics
Topic
Measures of Dispersion
Let the median and the mean deviation about the median of 7… | JEE Main 2024 PYQ with Solution · DhiX AI