Mathematics · Hyperbola

JEE Main 2025 — 22 January, Morning Shift — Question 20

Let the foci of a hyperbola be (1,14)(1,14) and (1,−12)(1,-12). If it passes through the point (1,6)(1,6), then the length of its latus-rectum is :

  1. Option A:

    256\frac{25}{6}

  2. Option B:

    245\frac{24}{5}

  3. Option C:

    2885\frac{288}{5}

    Correct
  4. Option D:

    1445\frac{144}{5}

Answer: C

Step-by-step solution

be=13,b=5b e=13, b=5

a2=b2(e2−1)\mathrm{a}^{2}=\mathrm{b}^{2}\left(\mathrm{e}^{2}-1\right)

=b2e2−b2=b^{2} \mathrm{e}^{2}-\mathrm{b}^{2}

=169−25=144=169-25=144

ℓ(LR)=2a2 b=2×1445=2885\ell(\mathrm{LR})=\frac{2 \mathrm{a}^{2}}{\mathrm{~b}}=\frac{2 \times 144}{5}=\frac{288}{5}

Solution figure

Answer key and solution verified before publishing.

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Exam
JEE Main 2025
Subject
Mathematics
Chapter
Hyperbola
Topic
Introduction to Hyperbola
Let the foci of a hyperbola be (1,14) and (1,-12) . If it passes… | JEE Main 2025 PYQ with Solution · DhiX AI