Mathematics · Complex Numbers

JEE Main 2026 — 2 April, Evening Shift — Question 24

Let the circle C1:∣z∣=r\mathrm{C}_{1}:\left|\mathrm{z}\right| = \mathrm{r} and C2:∣z−3−4i∣=5\mathrm{C}_{2}:\left|\mathrm{z} - 3 - 4\mathrm{i}\right| = 5, z∈C\mathrm{z}\in \mathbb{C}, be such that C2\mathrm{C}_{2} lies within C1\mathrm{C}_{1}. If z1\mathrm{z}_{1} moves on C1\mathrm{C}_{1}, z2\mathrm{z}_{2} moves on C2\mathrm{C}_{2} and min⁡∣z1−z2∣=2\min \left|\mathrm{z}_{1} - \mathrm{z}_{2}\right| = 2, then max⁡∣z1−z2∣\max \left|\mathrm{z}_{1} - \mathrm{z}_{2}\right| is equal to :-

  1. Option A:

    12

  2. Option B:

    17

  3. Option C:

    22

    Correct
  4. Option D:

    24

Answer: C

Step-by-step solution

∣z∣=r|\mathrm{z}|=\mathrm{r} OA=r\mathrm{OA}=\mathrm{r} minimum ∣z1−z2∣=2\left|\mathrm{z}_{1}-\mathrm{z}_{2}\right|=2 ⇒r−10=2⇒r=12\Rightarrow \mathrm{r}-10=2 \Rightarrow \mathrm{r}=12 maximum value of CB ∣z1−z2∣=r+10=12+10=22\left|\mathrm{z}_{1}-\mathrm{z}_{2}\right|=\mathrm{r}+10=12+10=22

Solution figure

Answer key and solution verified before publishing.

Practise Complex Numbers

Start with this question, then two more from the same chapter — with a tutor that explains every step. Free.

Exam
JEE Main 2026
Subject
Mathematics
Chapter
Complex Numbers
Topic
Geometry of Complex Numbers
Let the circle C 1 : z = r and C 2 : z - 3 - 4 i = 5 , z in mathbb C… | JEE Main 2026 PYQ with Solution · DhiX AI