Mathematics · Hyperbola

JEE Main 2026 — 2 April, Evening Shift — Question 33

Let O be the origin, and P and Q be two points on the rectangular hyperbola xy=12\mathbf{x}\mathbf{y} = 12 such that the mid point of the line segment PQ is (12,−12)\left(\frac{1}{2}, -\frac{1}{2}\right). Then the area of the triangle OPQ equals:

  1. Option A:

    32\frac{3}{2}

  2. Option B:

    52\frac{5}{2}

  3. Option C:

    72\frac{7}{2}

    Correct
  4. Option D:

    92\frac{9}{2}

Answer: C

Step-by-step solution

Equation of chord whose midpoint is (12,−12)\left(\frac{1}{2}, \frac{-1}{2}\right) xx1+yy1=2\frac{\mathrm{x}}{\mathrm{x}_{1}}+\frac{\mathrm{y}}{\mathrm{y}_{1}}=2 2x−2y=22 \mathrm{x}-2 \mathrm{y}=2 x−y=1x-y=1 solving with xy=12\mathrm{xy}=12 P(−3,−4),Q(4,3)\mathrm{P}(-3,-4), \mathrm{Q}(4,3) Area (△OPQ)=12∣−3×3−(−4)(4)∣=72(\triangle \mathrm{OPQ})=\frac{1}{2}|-3 \times 3-(-4)(4)|=\frac{7}{2}

Answer key and solution verified before publishing.

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Exam
JEE Main 2026
Subject
Mathematics
Chapter
Hyperbola
Topic
Rectangular Hyperbola
Let O be the origin, and P and Q be two points on the rectangular… | JEE Main 2026 PYQ with Solution · DhiX AI