Mathematics · Statistics

JEE Main 2024 — 4 April, Shift 1 — Question 13

Let a,b∈Ra, b \in R. Let the mean and the variance of 6 observations −3,4,7,−6,a,b-3,4,7,-6, \mathrm{a}, \mathrm{b} be 2 and 23 , respectively. The mean deviation about the mean of these 6 observations is :

  1. Option A:

    133\frac{13}{3}

    Correct
  2. Option B:

    163\frac{16}{3}

  3. Option C:

    113\frac{11}{3}

  4. Option D:

    143\frac{14}{3}

Answer: A

Step-by-step solution

∑xi6=2\frac{\sum \mathrm{x}_{\mathrm{i}}}{6}=2 and ∑xi2 N−μ2=23\frac{\sum \mathrm{x}_{\mathrm{i}}^{2}}{\mathrm{~N}}-\mu^{2}=23

α+β=10\alpha+\beta=10

α2+β2=52\alpha^{2}+\beta^{2}=52

solving we get α=4,β=6\alpha=4, \beta=6

∑∣xi−x‾∣6=5+2+5+8+2+46=133\frac{\sum\left|\mathrm{x}_{\mathrm{i}}-\overline{\mathrm{x}}\right|}{6}=\frac{5+2+5+8+2+4}{6}=\frac{13}{3}

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Statistics
Topic
Measures of Dispersion
Let a, b in R . Let the mean and the variance of 6 observations… | JEE Main 2024 PYQ with Solution · DhiX AI