Mathematics · Methods of Differentiation

JEE Main 2024 — 4 April, Shift 1 — Question 19

Let f(x)=x5+2ex/4f(\mathrm{x})=\mathrm{x}^{5}+2 \mathrm{e}^{\mathrm{x} / 4} for all x∈\mathrm{x} \in R. Consider a function g(x)g(x) such that (gof) (x)=x(x)=x for all x∈Rx \in R. Then the value of 8 g′(2)8 \mathrm{~g}^{\prime}(2) is :

  1. Option A:

    16

    Correct
  2. Option B:

    4

  3. Option C:

    8

  4. Option D:

    2

Answer: A

Step-by-step solution

f(x)=2f(x)=2 when x=0\mathrm{x}=0

∵g′(f(x))f′(x)=1\because g^{\prime}(f(x)) f^{\prime}(x)=1

g′(2)=1f′(0)\mathrm{g}^{\prime}(2)=\frac{1}{\mathrm{f}^{\prime}(0)}

∵f′(x)=5x4+24ex/4\because f^{\prime}(\mathrm{x})=5 \mathrm{x}^{4}+\frac{2}{4} \mathrm{e}^{\mathrm{x} / 4}

g′(2)=2g^{\prime}(2)=2

Ans =16=16

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Methods of Differentiation
Topic
First, second, third derivative of inverse of a function
Let f( x )= x 5 +2 e x / 4 for all x in R. Consider a function g(x)… | JEE Main 2024 PYQ with Solution · DhiX AI