Mathematics · Statistics

JEE Main 2024 — 30 January, Shift 1 — Question 16

Let MM denote the median of the following frequency distribution.

Class0-44-88-1212-1616-20
Frequency391086

Then 20 M is equal to :

  1. Option A:

    416

  2. Option B:

    104

  3. Option C:

    52

  4. Option D:

    208

    Correct

Answer: D

Step-by-step solution

ClassFrequencyCumulative Frequency
0-433
4-8912
8-121022
12-16830
16-20636

M=l+(N2−Cf)hM=l+\left(\frac{\frac{N}{2}-C}{f}\right) h

M=8+18−1210×4M=8+\frac{18-12}{10} \times 4

M=10.4\mathrm{M}=10.4

20M=20820 \mathrm{M}=208

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
Statistics
Topic
Measures of Central Tendency
Let M denote the median of the following frequency distribution.… | JEE Main 2024 PYQ with Solution · DhiX AI