Mathematics · 3D Geometry

JEE Main 2024 — 31 January, Shift 2 — Question 6

Let (α,β,γ)(\alpha, \beta, \gamma) be mirror image of the point (2,3,5)(2,3,5) in the line x−12−y−23−z−34\frac{x-1}{2}-\frac{y-2}{3}-\frac{z-3}{4}. Then 2α+3β+4γ2 \alpha+3 \beta+4 \gamma is equal to

  1. Option A:

    32

  2. Option B:

    33

    Correct
  3. Option C:

    31

  4. Option D:

    34

Answer: B

Step-by-step solution

∵PR→⊥(2,3,4)\because \overrightarrow{\mathrm{PR}} \perp(2,3,4)

∴PR→⋅(2,3,4)=0\therefore \overrightarrow{\mathrm{PR}} \cdot(2,3,4)=0

(α−2,β−3,γ−5)⋅(2,3,4)=0(\alpha-2, \beta-3, \gamma-5) \cdot(2,3,4)=0

⇒2α+3β+4γ=4+9+20=33\Rightarrow 2 \alpha+3 \beta+4 \gamma=4+9+20=33

Answer key and solution verified before publishing.

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Exam
JEE Main 2024
Subject
Mathematics
Chapter
3D Geometry
Topic
Vector & Cartesian forms of lines and planes
Let (α, β, γ) be mirror image of the point (2,3,5) in the line… | JEE Main 2024 PYQ with Solution · DhiX AI